1840 Indiana gubernatorial election
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 County results Bigger: 50–60% 60–70% Howard: 50–60% 60–70% 70–80% 80–90% No Vote/Data: | |||||||||||||||||
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The 1840 Indiana gubernatorial election was held on 3 August 1840 in order to elect the Governor of Indiana. Whig nominee and former member of the Indiana House of Representatives Samuel Bigger defeated Democratic nominee and incumbent member of the U.S. House of Representatives from Indiana's 7th district Tilghman Howard.[1]
General election
On election day, 3 August 1840, Whig nominee Samuel Bigger won the election by a margin of 8,658 votes against his opponent Democratic nominee Tilghman Howard, thereby retaining Whig control over the office of Governor. Bigger was sworn in as the 7th Governor of Indiana on 9 December 1840.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Whig | Samuel Bigger | 62,932 | 53.69 | |
| Democratic | Tilghman Howard | 54,274 | 46.31 | |
| Total votes | 117,206 | 100.00 | ||
| Whig hold | ||||
References
- ↑ "Samuel Bigger". National Governors Association. Retrieved November 29, 2023.
- ↑ "IN Governor". ourcampaigns.com. March 11, 2005. Retrieved November 29, 2023.
- ↑ Indiana General Assembly. Journal of the House of Representatives. 1840 sess., 3, accessed 29 November 2023