1844 United States presidential election in New Jersey
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File:New Jersey Presidential Election Results 1844.svg County Results
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The 1844 United States presidential election in New Jersey took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President. New Jersey voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won New Jersey by a margin of 1.09 percent; however, Polk would be the last Democrat to carry Cape May County until Woodrow Wilson in 1912.[1] This is the last time a Democrat won without carrying Hudson County.
Results
| 1844 United States presidential election in New Jersey[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 38,318 | 50.46% | 7 | 100.00% | ||
| Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 37,495 | 49.37% | 0 | 0.00% | ||
| Liberty | James G. Birney of Michigan | Thomas Morris of Ohio | 131 | 0.17% | 0 | 0.00% | ||
| Total | 75,944 | 100.00% | 7 | 100.00% | ||||
See also
References
- ↑ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 258-259 ISBN 0786422173
- ↑ "1844 Presidential General Election Results – New Jersey". U.S. Election Atlas. Retrieved December 23, 2013.
