2014 Sacramento Challenger – Doubles
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Doubles | |
---|---|
2014 Sacramento Challenger | |
Champions | Australia Adam Hubble Australia John-Patrick Smith |
Runners-up | Canada Peter Polansky Canada Adil Shamasdin |
Score | 6–3, 6–2 |
John-Patrick Smith and Matt Reid were the defending champions, however they chose not to participate with each other. Smith partners Adam Hubble, whilst Reid partners Jose Statham. Adam Hubble and John-Patrick Smith won the title by defeating Peter Polansky and Adil Shamasdin 6–3, 6–2 in the final.
Seeds
- New Zealand Marcus Daniell / New Zealand Artem Sitak (semifinals)
- Canada Peter Polansky / Canada Adil Shamasdin (final)
- United States Bradley Klahn / United States Tim Smyczek (withdrew)
- United States Sekou Bangoura / United States Tennys Sandgren (first round)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking