2019 Oracle Challenger Series – Indian Wells – Women's doubles
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Indian Wells – Women's doubles | |
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2019 Oracle Challenger Series – Indian Wells | |
Champions | |
Runners-up | |
Score | 7–6(9–7), 6–4 |
Kristýna Plíšková and Evgeniya Rodina won the title, defeating defending champions Taylor Townsend and Yanina Wickmayer,[1] in the final, 7–6(9–7), 6–4.
Seeds
Fanny Stollár /
Heather Watson (first round)
Nao Hibino /
Oksana Kalashnikova (quarterfinals)
Olga Danilović /
Nadiia Kichenok (first round)
Sorana Cîrstea /
Sara Sorribes Tormo (first round)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | 6 | 3 | [5] | ||||||||||||||||||||||||
3 | 6 | [10] | 6 | 3 | [11] | ||||||||||||||||||||||
1 | 4 | 3 | 6 | [13] | |||||||||||||||||||||||
6 | 6 | 5 | 3 | ||||||||||||||||||||||||
4 | 5 | 6 | [5] | 7 | 6 | ||||||||||||||||||||||
7 | 3 | [10] | 2 | 6 | [9] | ||||||||||||||||||||||
6 | 7 | 6 | 1 | [11] | |||||||||||||||||||||||
2 | 5 | 79 | 6 | ||||||||||||||||||||||||
WC | 64 | 6 | [3] | 67 | 4 | ||||||||||||||||||||||
77 | 4 | [10] | 6 | 6 | |||||||||||||||||||||||
4 | 6 | [10] | 3 | 0 | |||||||||||||||||||||||
3 | 6 | 3 | [6] | 2 | 4 | ||||||||||||||||||||||
6 | 6 | 6 | 6 | ||||||||||||||||||||||||
4 | 0 | 6 | 6 | ||||||||||||||||||||||||
2 | 0 | 2 | 2 | 3 | |||||||||||||||||||||||
2 | 6 | 6 |
References
- ↑ "Oracle Challenger Indian Wells: Yanina takes home 2nd doubles title of the year". yaninawickmayer.com., March 5, 2018