Smooth morphism

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In algebraic geometry, a morphism f:XS between schemes is said to be smooth if

(iii) means that each geometric fiber of f is a nonsingular variety (if it is separated). Thus, intuitively speaking, a smooth morphism gives a flat family of nonsingular varieties. If S is the spectrum of an algebraically closed field and f is of finite type, then one recovers the definition of a nonsingular variety. A singular variety is called smoothable if it can be put in a flat family so that the nearby fibers are all smooth. Such a family is called a smoothning of the variety.

Equivalent definitions

There are many equivalent definitions of a smooth morphism. Let f:XS be locally of finite presentation. Then the following are equivalent.

  1. f is smooth.
  2. f is formally smooth (see below).
  3. f is flat and the sheaf of relative differentials ΩX/S is locally free of rank equal to the relative dimension of X/S.
  4. For any xX, there exists a neighborhood SpecB of x and a neighborhood SpecA of f(x) such that B=A[t1,,tn]/(P1,,Pm) and the ideal generated by the m-by-m minors of (Pi/tj) is B.
  5. Locally, f factors into Xg𝔸SnS where g is étale.

A morphism of finite type is étale if and only if it is smooth and quasi-finite. A smooth morphism is stable under base change and composition. A smooth morphism is universally locally acyclic.

Examples

Smooth morphisms are supposed to geometrically correspond to smooth submersions in differential geometry; that is, they are smooth locally trivial fibrations over some base space (by Ehresmann's theorem).

Smooth Morphism to a Point

Let f be the morphism of schemes

Spec([x,y](f=y2x3x1))Spec()

It is smooth because of the Jacobian condition: the Jacobian matrix

[3x21,y]

vanishes at the points (1/3,0),(1/3,0) which has an empty intersection with the polynomial, since

f(1/3,0)=113133f(1/3,0)=13+1331

which are both non-zero.

Trivial Fibrations

Given a smooth scheme Y the projection morphism

Y×XX

is smooth.

Vector Bundles

Every vector bundle EX over a scheme is a smooth morphism. For example, it can be shown that the associated vector bundle of 𝒪(k) over n is the weighted projective space minus a point

O(k)=(1,,1,k){[0::0:1]}n

sending

[x0::xn:xn+1][x0::xn]

Notice that the direct sum bundles O(k)O(l) can be constructed using the fiber product

O(k)O(l)=O(k)×XO(l)

Separable Field Extensions

Recall that a field extension KL is called separable iff given a presentation

L=K[x](f(x))

we have that gcd(f(x),f(x))=1. We can reinterpret this definition in terms of Kähler differentials as follows: the field extension is separable iff

ΩL/K=0

Notice that this includes every perfect field: finite fields and fields of characteristic 0.

Non-Examples

Singular Varieties

If we consider Spec of the underlying algebra R for a projective variety X, called the affine cone of X, then the point at the origin is always singular. For example, consider the affine cone of a quintic 3-fold given by

x05+x15+x25+x35+x45

Then the Jacobian matrix is given by

[5x045x145x245x345x44]

which vanishes at the origin, hence the cone is singular. Affine hypersurfaces like these are popular in singularity theory because of their relatively simple algebra but rich underlying structures. Another example of a singular variety is the projective cone of a smooth variety: given a smooth projective variety Xn its projective cone is the union of all lines in n+1 intersecting X. For example, the projective cone of the points

Proj([x,y](x4+y4))

is the scheme

Proj([x,y,z](x4+y4))

If we look in the z0 chart this is the scheme

Spec([X,Y](X4+Y4))

and project it down to the affine line 𝔸Y1, this is a family of four points degenerating at the origin. The non-singularity of this scheme can also be checked using the Jacobian condition.

Degenerating Families

Consider the flat family

Spec([t,x,y](xyt))𝔸t1

Then the fibers are all smooth except for the point at the origin. Since smoothness is stable under base-change, this family is not smooth.

Non-Separable Field Extensions

For example, the field 𝔽p(tp)𝔽p(t) is non-separable, hence the associated morphism of schemes is not smooth. If we look at the minimal polynomial of the field extension,

f(x)=xptp

then df=0, hence the Kähler differentials will be non-zero.

Formally smooth morphism

One can define smoothness without reference to geometry. We say that an S-scheme X is formally smooth if for any affine S-scheme T and a subscheme T0 of T given by a nilpotent ideal, X(T)X(T0) is surjective where we wrote X(T)=HomS(T,X). Then a morphism locally of finite presentation is smooth if and only if it is formally smooth. In the definition of "formally smooth", if we replace surjective by "bijective" (resp. "injective"), then we get the definition of formally étale (resp. formally unramified).

Smooth base change

Let S be a scheme and char(S) denote the image of the structure map SSpec. The smooth base change theorem states the following: let f:XS be a quasi-compact morphism, g:SS a smooth morphism and a torsion sheaf on Xet. If for every 0p in char(S), p: is injective, then the base change morphism g*(Rif*)Rif'*(g'*) is an isomorphism.

See also

References