2019 Bucharest Open – Doubles
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Doubles | |
---|---|
2019 Bucharest Open | |
Champions | Slovakia Viktória Kužmová Czech Republic Kristýna Plíšková |
Runners-up | Romania Jaqueline Cristian Romania Elena-Gabriela Ruse |
Score | 6–4, 7–6(7–3) |
Irina-Camelia Begu and Andreea Mitu were the defending champions,[1] but chose to participate with different partners. Begu played alongside Raluca Olaru, while Mitu teamed up with Lara Arruabarrena. Both teams lost to Jaqueline Cristian and Elena-Gabriela Ruse in the semifinals and quarterfinals, respectively. Viktória Kužmová and Kristýna Plíšková won the title, defeating Cristian and Ruse in the final, 6–4, 7–6(7–3).
Seeds
- Romania Irina-Camelia Begu / Romania Raluca Olaru (semifinals)
- Serbia Aleksandra Krunić / United States Bethanie Mattek-Sands (withdrew)
- Spain Lara Arruabarrena / Romania Andreea Mitu (quarterfinals)
- Slovakia Viktória Kužmová / Czech Republic Kristýna Plíšková (champions)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
References
- ↑ "'I can get even better': New mom Mitu partners Begu to win doubles in Bucharest". www.wtatennis.com.